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sort_ref_dir(): simplify logic
Use the more usual indexing idiom for clarity. Signed-off-by: Michael Haggerty <mhagger@alum.mit.edu> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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21
refs.c
21
refs.c
@ -227,11 +227,13 @@ static int is_dup_ref(const struct ref_entry *ref1, const struct ref_entry *ref2
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}
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/*
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* Sort the entries in dir (if they are not already sorted).
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* Sort the entries in dir (if they are not already sorted)
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* and remove any duplicate entries.
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*/
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static void sort_ref_dir(struct ref_dir *dir)
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{
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int i, j;
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struct ref_entry *last = NULL;
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/*
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* This check also prevents passing a zero-length array to qsort(),
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@ -242,16 +244,15 @@ static void sort_ref_dir(struct ref_dir *dir)
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qsort(dir->entries, dir->nr, sizeof(*dir->entries), ref_entry_cmp);
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/* Remove any duplicates from the ref_dir */
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i = 0;
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for (j = 1; j < dir->nr; j++) {
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if (is_dup_ref(dir->entries[i], dir->entries[j])) {
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free_ref_entry(dir->entries[j]);
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continue;
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/* Remove any duplicates: */
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for (i = 0, j = 0; j < dir->nr; j++) {
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struct ref_entry *entry = dir->entries[j];
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if (last && is_dup_ref(last, entry))
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free_ref_entry(entry);
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else
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last = dir->entries[i++] = entry;
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}
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dir->entries[++i] = dir->entries[j];
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}
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dir->sorted = dir->nr = i + 1;
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dir->sorted = dir->nr = i;
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}
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#define DO_FOR_EACH_INCLUDE_BROKEN 01
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